PROBABILITY RULES

Hello, SARAHI071

\(\displaystyle P(B)\,=\,0.2,\;\;P(A)\,=\,0.7,\;\;P(A\,\cap\,B)\,=\,0.14\)

Find \(\displaystyle \,(A|B)\)
Are you familiar with Bayes' Formula?

\(\displaystyle \;\;\;P(A|B)\;=\;\frac{P(A\,\cap\,B)}{P(B)}\)
 
YES I AM FAMILIAR BUT IT GOES LIKE THIS
P(B|A)=P(A AND B)
P(A)
AND I AM NOT SURE HOT TO CHANGE THAT TO

P (A|B)= P(B AND A)
P(B)
BECUASE OTHERWISE IT WILL BE

P(B|A)=.14/.2=.7
SO P(B|A)=.7[/quote]
 
SORRY I PLUG THE NUMBER WRONG
P(B|A)=.14/.7
P(B|0)=.2
BUT I DON'T KNOW WHAT (B AND A) IS SO I'M CONFUSED PLEASE HELP ME
 
DID I WORKED THE PROBLEM CORRECTLY AND HOW WOULD I KNOW IF THEY ARE INDEPENDENT OR NOT
 
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