Probability: rolling one 6 w/ four die, one OR MORE 6s w/
- Thread starter bbash30
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Re: Probability Again!
1) The plural of "die" is "dice".
Pr(rolling a 6 with one die) = 1/6
Pr(rolling exactly one 6 with two dice) = PR(hitting the first and not the second) + Pr(Hitting the second and not the first) = (1/6)(5/6) + (5/6)(1/6) = 10/36
You can make a tree. There are several ways to go about getting all the way up to four dice.
1) The plural of "die" is "dice".
Pr(rolling a 6 with one die) = 1/6
Pr(rolling exactly one 6 with two dice) = PR(hitting the first and not the second) + Pr(Hitting the second and not the first) = (1/6)(5/6) + (5/6)(1/6) = 10/36
You can make a tree. There are several ways to go about getting all the way up to four dice.