Probability Question Test a claim

[srt927]

Test the claim that the mean body temperature of healthy adults is 98.6 degrees F. where a Sample of size 106 yielded X bar = 98.20 and S=.62 use alpha= .01

I'm stumped I know Im supposed to use

X bar - Mue
divieded by
srtd deviation divieded by the square root of N

But how do you set it up?

 

[galactus]

The test is two-tailed.

\(\displaystyle \L\\H_{0}:{\mu}=98.6\)

\(\displaystyle \L\\H_{a}:{\mu}\neq{98.6}\)

\(\displaystyle \L\\z=\frac{98.2-98.6}{\frac{0.62}{\sqrt{106}}}\)

Because the test is two-tailed and you have a 1% level of significance, your critical value is \(\displaystyle \pm{2.575}\)(from the table).

Calculate your test statistic z, if it falls in the rejection region, then reject the null hyp. If it doesn't, fail to reject.

Also, you can check the p-value. If it is less than 0.01, then reject. If it's > 0.01, then fail to reject.

Interpret the results.