Here's my problem:
In this exercise, assume that the readings on the thermometers are normally distributed with a mean of 0 degrees and a standard deviation of 1.00 degrees C. Find the indicated probability, where Z is the reading in degrees.
P(z < -2.575 or z < 2.575)
OK, this is what I have but it ended up being wrong, maybe someone could tell me where I went wrong or if I have no clue at all.
P(z < -2.575 or z < 2.575) =
P(z < -2.575) + P(z < 2.575) =
to find the z Score I used the following formulas:
-2.575 - 0 / 1 = -2.575 which is what you need to convert to a z Score of .0049.
2.575 - 0/ 1 = 2.575 which is what you need to convert to a z Score of .9948
I then would take .9948 and add it to .0049 to get .9997 which is wrong...it should be .0100
Any and all help is appreciated, thank you in advance...MommaT
In this exercise, assume that the readings on the thermometers are normally distributed with a mean of 0 degrees and a standard deviation of 1.00 degrees C. Find the indicated probability, where Z is the reading in degrees.
P(z < -2.575 or z < 2.575)
OK, this is what I have but it ended up being wrong, maybe someone could tell me where I went wrong or if I have no clue at all.
P(z < -2.575 or z < 2.575) =
P(z < -2.575) + P(z < 2.575) =
to find the z Score I used the following formulas:
-2.575 - 0 / 1 = -2.575 which is what you need to convert to a z Score of .0049.
2.575 - 0/ 1 = 2.575 which is what you need to convert to a z Score of .9948
I then would take .9948 and add it to .0049 to get .9997 which is wrong...it should be .0100
Any and all help is appreciated, thank you in advance...MommaT