Assume that the weights of quarters are normally distributed with a mean of 5.67g and a standard deviation 0.070g. A vending machine will only accept coins weighing between 5.48g and 5.82g. What percentage of legal quarters will be rejected?
I know the -x is 5.67 mean
s is 0.070g
and x is between 5.48g and 5.82g
and formula is z= x-mean divided by s or x-u divided by 0
5.82-5.67 divided by 0.070g= 2.142
but the answer is supposed to be 1.96% need help on what I am not doing right
I know the -x is 5.67 mean
s is 0.070g
and x is between 5.48g and 5.82g
and formula is z= x-mean divided by s or x-u divided by 0
5.82-5.67 divided by 0.070g= 2.142
but the answer is supposed to be 1.96% need help on what I am not doing right