Prison Population

[judocallin]

Problem:
For a recent year,0.99 of the incarcerted population is adults and 0.07 is female. If an incarcerated person is selected at random,find the probability that the person is a female given that she is an adult.

incarcerated population(adults)=0.99
incarcerated population(female)=0.07
P(F/A)= P(F and A)/P(A)

How do I get the number of females in the 0.99 incarcerated adults?


What I did was just to divide (0.07/0.99),assuming that all 0.07 were adults. Because 0.99 is close to 1 the answer will be close to 0.07. I also tried this: (0.99*0.07)/0.99, the answer is also 0.07. Both yielded the same answer. But what if the incarcerated adult population is 0.62?

 

[soroban]

Hello, judocallin!

We need more information . . .

For a recent year, 99% of the incarcerated population is adults and 7% is female.
If an incarcerated person is selected at random,
. . find the probability that the person is a female given that she is an adult.

incarcerated population (adults) = 0.99
incarcerated population (female) = 0.07
P(F|A) = P(F and A)/P(A)

How do I get the number of females in the 0.99 incarcerated adults? . We can't

We are given only this information:

. . \(\displaystyle \begin{array}{c||c|c||c|} & \text{Female} & \text{Male} & \text{Total} \\ \hline\hline\text{Adult} & w & x & 0.99 \\ \hline \text{Minor} & y & z & 0.01 \\ \hline \hline \text{Total} & 0.07 & 0.93 & 1.00 \\ \hline\end{array}\)


\(\displaystyle \text{We need one of }\,w,x,y\text{ or }z\,\text{ to solve the problem.}\)

 

[judocallin]

thanks.

so what would we the best way to present it?

should i answer, "no answer"