PreCalculus Ellipse

[bjaaron]

The question is asking me to graph this equation: y²+10y+x+28
I must put it into standard form which is: (x-h)²/number+ (y-k)²/number=1
and complete the square and I am unsure how to do this with this problem.

 

[Bob Brown MSEE]

The question is asking me to graph this equation: y²+10y+x+28
I must put it into standard form which is: (x-h)²/number+ (y-k)²/number=1
and complete the square and I am unsure how to do this with this problem.

y²+10y+x+28=0?
This is not an ellipse. Check your original problem and we can go forward.

 

[bjaaron]

y²+10y+x+28=0?
This is not an ellipse. Check your original problem and we can go forward.

It's not in standard form yet, I have to work it out by completing the square

 

[Bob Brown MSEE]

This is not an ellipse. Check your original problem and we can go forward.
It cannot be put in "standard form"
1) Were you told this is an ellipse.
2) Did you verify that the formula is correct as an equation?
The formula IS NOT correct because it is not equal to zero.

 

[bjaaron]

This is not an ellipse. Check your original problem and we can go forward.
It cannot be put in "standard form"
1) Were you told this is an ellipse.
2) Did you verify that the formula is correct?

Sorry I got the wrong problem from the book the equation is 25x²+9y²-100x+54y-44=0

 

[Bob Brown MSEE]

Given:25x²+9y²-100x+54y-44=0
You need to solve two problems first.

1) 25x²-100x+a = 25(x-b)²
2) 9y²+54y+c = 9(x-d)^​2

 

[bjaaron]

Given:25x²+9y²-100x+54y-44=0
You need to solve two problems first.

1) 25x²-100x+a = 25(x-b)²
2) 9y²+54y+c = 9(x-d)^​2

Okay I got 25(x-2)²+9(y+3)²=225

 

[Bob Brown MSEE]

Okay I got 25(x-2)²+9(y+3)²=225

very close

 

[bjaaron]

very close

Now do I divide by 225?

 

[Bob Brown MSEE]

25(x-2)²+9(y+3)²=225
just divide by 225, good work!