EulerIsMyDad
New member
- Joined
- Jun 28, 2019
- Messages
- 4
I got 1/(x+1)^3+1/(x+1)^2+1/(x+1)Hello, and welcome to FMH!
Using partial fraction decomposition, what do you get for:
[MATH]\frac{x^2+3x+3}{(x+1)^3}[/MATH] ?
That looks good.I got 1/(x+1)^3+1/(x+1)^2+1/(x+1)
i have tried this but it doesnt seem to get me anywhere as when i do parts i have e^-xsinx as my u and the three partial fractions as my dV/dx, and it doesnt get any simpler.That looks good.
Now use that in your original "expression" and integrate by parts. I have not done the integration - but looks like there will be three parts to integrate. Could be kind of long!!
Can you do the following indefinite integration:i have tried this but it doesnt seem to get me anywhere as when i do parts i have e^-xsinx as my u and the three partial fractions as my dV/dx, and it doesnt get any simpler.
yea i get e^-x/2(sinx+cosx)Can you do the following indefinite integration:
\(\displaystyle \displaystyle{\int e^{-x} * sin(x) dx}\)