factor x^3-3x^2-x+3=0
L Loren Senior Member Joined Aug 28, 2007 Messages 1,299 Aug 26, 2010 #2 jboyd said: factor x^3-3x^2-x+3=0 Click to expand... You might rewrite it as... (x[sup:1f1c5byw]3[/sup:1f1c5byw] - 3x[sup:1f1c5byw]2[/sup:1f1c5byw]) - (x - 3) = 0 Now, factor the left side by grouping and go from there.
jboyd said: factor x^3-3x^2-x+3=0 Click to expand... You might rewrite it as... (x[sup:1f1c5byw]3[/sup:1f1c5byw] - 3x[sup:1f1c5byw]2[/sup:1f1c5byw]) - (x - 3) = 0 Now, factor the left side by grouping and go from there.
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Aug 27, 2010 #3 \(\displaystyle x^3-3x^2-x+3 \ = \ 0\) \(\displaystyle x^2(x-3)-1(x-3) \ = \ 0\) \(\displaystyle (x^2-1)(x-3) \ = \ 0\) \(\displaystyle (x+1)(x-1)(x-3) \ = \ 0\)
\(\displaystyle x^3-3x^2-x+3 \ = \ 0\) \(\displaystyle x^2(x-3)-1(x-3) \ = \ 0\) \(\displaystyle (x^2-1)(x-3) \ = \ 0\) \(\displaystyle (x+1)(x-1)(x-3) \ = \ 0\)
