pre calculus: Rationalizing Expressions

[a-mandible..!(:]

x^2-36 x^2+x
-------- X --------
x x^3-6x^2

= (x+6)(x-6) x^2+X
----------------- X ---------
x x^3-6x^2


and now im stuckkk... i knew to factor the first part of it but i dont know how to do the rest of it..
x^2 would be like x squared...i dont know how to make the numbers into exponents and the ------- are fraction bars.
X is times and x is the variable x. please help meeee.. :?

 

[BigGlenntheHeavy]

\(\displaystyle If \ this \ is \ what \ you \ meant:\)

\(\displaystyle \frac{(x^2-36)(x^2+x)}{x(x^3-6x^2)}, \ then \ we \ have \ \frac{(x+6)(x-6)x(x+1)}{x[x^2(x-6)]}\)

\(\displaystyle = \ \frac{(x+6)(x-6)x(x+1)}{x^3(x-6)} \ = \ \frac{(x+6)(x+1)}{x^2}, \ any \ restrictions?\)