pre-calculus questions

[watchthesky30]

hi. i just want to know if i got the correct answers for these questions. you don't need to do it for me, i just want to know if it's right or wrong. thanks in advance!

1) (c^4d³/cd²)(d²/c³)³
i got the answer c^4d^7/c³

2) (c+1/c)²
i got the answer c^4+1/c²

3) ((?h²+1)+1)(?h²+1) -1)
i got the answer h²+0

and i want to know if it is possible to solve x²-6x+17 further...without using the quadratic formula

 

[mmm4444bot]

It's hard for me to interpret your typing because you've left off crucial grouping symbols. I'll have to guess.

(And, please stop using those microscopic superscripts. I'm already one-third blind.)

If the following expression matches yours in exercise (1), then your answer is wrong.

\(\displaystyle \frac{c^4 \; d^3}{c \; d^2} \cdot \left( \frac{d^2}{c^3} \right)^3\)

It's typed like so:

(c^4 d^3/[c d^2]) * (d^2/c^3)^3

If either of the following expressions match yours in exercise (2), then your answer is wrong.

\(\displaystyle \left( \frac{c + 1}{c} \right)^2\)

It's typed like so:

([c + 1]/c)^2

\(\displaystyle \left( c \;+\; \frac{1}{c} \right)^2\)

It's typed like so:

(c + [1/c])^2

Your result for exercise (3) is correct, but can you simplify h^2 + 0 ?

Regarding "solving" the 2nd-degree polynomial x^2 - 6x + 17, there is nothing to solve. You need an equation, to solve. This polynomial is not an equation; it's an expression.

Perhaps you're trying to ask about "simplifying"? If so, then I'll tell you that it's already fully simplified.

Perhaps you're asking about factoring?

I dunno.

If you'd like more help with any of this, please clarify the actual expressions and show us your steps.

Cheers ~ Mark