Pre Calculus Graphing. Don't Understand.

[monkey12]

Here's the problem.

Use your graphing utility to graph each side of the equation in the same viewing rectangle. Then use the x-coordinate of the intersection point to find the equation's solution set. Verify this value by direct substitution into the equation.

3^x = 2x+3

Here's the answer(back of the book):{-1.391606, 1.6855579}
I just do not understand how to get this answer.

Any help is appreciated.

 

[mmm4444bot]

What graphing utility are you using?

 

[monkey12]

What graphing utility are you using?

I guess the y= button, not sure.

 

[mmm4444bot]

A graphing utility is not a button.

Let me rephrase the question.

What machine are you trying to use for plotting the graph?

 

[monkey12]

A graphing utility is not a button.

Let me rephrase the question.

What machine are you trying to use for plotting the graph?

I am using the TI-84 (Texas Instruments). Sorry about that.

 

[mmm4444bot]

Put 3^X in Y1

Put 2X+3 in Y2

Change the window settings to:

xMin = -2

xMax = 2

yMin = -1

yMax = 8

On the graph, you should see two intersection points.

Zoom in on each of them, to see the X-coordinate.

Substitute these values of X (one at a time) into the original equation, to confirm.

 

[monkey12]

I got it! Thank you very much!

 

[mmm4444bot]

For future reference, here is a link to TI-84 Instructional Videos. Cheers :cool: