Primitive_animal
New member
- Joined
- Jan 13, 2012
- Messages
- 1
hi guys, i have been working on this problem for a solid two hours and I'm not getting the right answer.
PROBLEM :A salesman drives from Ajax to Barrington, a distance of 130 mi, at a steady speed. He then increases his speed by 12 mi/h to drive the 156 mi from Barrington to Collins. If the second leg of his trip took 4 min more time than the first leg, how fast was he driving between Ajax and Barrington?
Ive approached this by trying to get a quadratic equation, (130/x)+1/12=156/(x+2) and i use the LCD and cancel out the fractions and i get the quadratic, and solve it... but I'm not getting the right answer. I DO NOT NEED JUST the answer for the problem. i want to know how it is done. Thanks for the assistance.
PROBLEM :A salesman drives from Ajax to Barrington, a distance of 130 mi, at a steady speed. He then increases his speed by 12 mi/h to drive the 156 mi from Barrington to Collins. If the second leg of his trip took 4 min more time than the first leg, how fast was he driving between Ajax and Barrington?
Ive approached this by trying to get a quadratic equation, (130/x)+1/12=156/(x+2) and i use the LCD and cancel out the fractions and i get the quadratic, and solve it... but I'm not getting the right answer. I DO NOT NEED JUST the answer for the problem. i want to know how it is done. Thanks for the assistance.