pre algebra

[tammyd]

need to find thex and y intercepts the problem is 2x+6y=12

 

[Deleted member 4993]

need to find thex and y intercepts the problem is 2x+6y=12

Please tell us the definitions of the:

x-intercept of a graph

and

y-intercept of a graph

 

[Larry daron]

I find it

2x+6y=12
2*3+6*1=12

So

x=3;
y=1;

 

[mmm4444bot]

I find it

x=3;
y=1;

Not quite, Larry. :cool:

You found one solution to 2x + 6y = 12. There are infinite solutions.

This exercise asks where the line crosses the axes (the intercepts).

We find the x-intercept by letting y = 0.

We find the y-intercept by letting x = 0.

 

[nyc_function]

x and y intercepts

need to find thex and y intercepts the problem is 2x+6y=12

To find the x-intercept, let y = 0 and solve for x. Let's do just that....

2x + 6y = 12

2x + 6(0) = 12

2x + 0 = 12

2x = 12

x = 12/2

x = 6.

To find the y-intercept, let x = 0 and solve for y.

2x + 6y = 12

2(0) + 6y = 12

0 + 6y = 12

6y = 12

y = 12/6

y = 2

The x-intercept is 6, which can be written as the point (6,0).

The y-intercept is 2, which can be written as the point (0,2).

What does this all mean anyway?

It means that the graph of the given equation 2x + 6y = 12 crosses the x-axis at the point (6,0) and crosses the y-axis at the point (0,2).

Is this clear?