Power

Hi,

what is an easy way to get the answer to

2 to the power of 50
That really depends on how you want to do it. If you are planning to use a calculator than simply compute 2^50. If my hand then maybe compute 2^5 and multiply that by itself. So you will have [2^5]^2=2^10. Now multiply that result by itself to get 2^20. Multiply by itself to get 2^40. Multiply this result by 2^10 which you already have. This result is your answer. It will be an extremely large number!
 
Hi,

what is an easy way to get the answer to

2 to the power of 50

Depends on what you want it for. Is an answer to a couple of percent good enough? If so
250 = (210)5 =10245 =1.0245 1015 ~ 1.12 1015
or
250 ~ 100.301 * 50 = 100.05 1015 ~ (e2.3)0.05 1015 = e0.115 1015 ~ 1.115 1015
 
What a simple question.

I don't find the question simple; it's not clearly stated.

You provided one of many answers possible to but a single interpretation.

Here's another.

Both are more or less repeats of what Jomo already posted in sentence number two. :cool:

By the way, if you drop the grouping symbols from 2^{50} at wolfram-alpha, you'll get more info. Although, I think their claim that 2^50 is 56 times the number of red blood cells in a human body is off quite a bit. For an average male with healthy weight, 46 times is more accurate. (Source: Mayo Clinic hematology stats)
 
By the way, if you drop the grouping symbols from 2^{50} at wolfram-alpha, you'll get more info. Although, I think their claim that 2^50 is 56 times the number of red blood cells in a human body is off quite a bit. For an average male with healthy weight, 46 times is more accurate. (Source: Mayo Clinic hematology stats)
Well that depends upon how much one knows about posting mathematics text.
I know LaTeX coding. Using ^{} will yield \(\displaystyle 2^{50}\) where as without {} we get \(\displaystyle 2^50\).
If you doubt that click the reply with quote option tab.
 
Well [getting extra information from wolfram-alpha] depends upon how much one knows about posting mathematics text.

No it does not (in this case), my friend, because I am not talking about "posting mathematics text".

I'm talking about entering the character string 2^50 in the input field at a particular on-line calculator. One does not require knowledge of LaTex coding to do that.

If you doubt this, try it yourself, and look again. ;)
 
you can dig a hole by hand or use a bulldozer

The OP does not indicate the type of hole or what it will be used for. That's why Jomo answered "depends".

I think we're covered. :)
 
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