Power series

Trumbone

New member
Joined
Oct 5, 2009
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24
Does anyone know how to find the power series of a[sup:1y7eze82]x[/sup:1y7eze82]?
and/or
Show that e[sup:1y7eze82]s+t[/sup:1y7eze82]= e[sup:1y7eze82]s[/sup:1y7eze82]e[sup:1y7eze82]t[/sup:1y7eze82]using algebra with power series?
 
For the first one:

\(\displaystyle a^x = e^{x \ln(a)} = \sum_{n=0}^{\infty} \frac{(x\ln a)^n}{n!}\)

For the second, are you supposed to use binomial expansion? It's probably possible that way, though I've personally only seen this derived from the limit definition of exp...
 
Thank you so much for your help, but I am a little confused about how you went from a[sup:gdjw5b1n]x[/sup:gdjw5b1n] to e[sup:gdjw5b1n]xln(a)[/sup:gdjw5b1n].
 
For any 1-1 function f on a member k of its domain, \(\displaystyle f^{-1}(f(k)) = k\)

Since \(\displaystyle e^x\) and \(\displaystyle \ln(x)\) are inverse functions and \(\displaystyle a>0\) means we have \(\displaystyle e^{\ln(a^x)} = a^x\).

We also know \(\displaystyle \ln(a^x) = x \ln(a)\)
 
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