I think this is correct
diff ln(x-5) = -1/ (5-x) -----> SIGMA x^n = 1/ (1-x) seems the right path.
so -1/(5-x) should look like 1/(1-x)
- 1/5* (1/(1- (x/5))) looks to match 1 / (1-x), however there is a - sign , so should it be - 1/5* (1/(1+ (x/5))) or am I just barking up the wrong tree?
If I diff geometric series ... SIGMA X^n to SIGMA nX^(n-1) , what do I do with the 1/5 and x/5 ? Just geeting confused at this point as to what the final pwr series representation should even look like?
tks
diff ln(x-5) = -1/ (5-x) -----> SIGMA x^n = 1/ (1-x) seems the right path.
so -1/(5-x) should look like 1/(1-x)
- 1/5* (1/(1- (x/5))) looks to match 1 / (1-x), however there is a - sign , so should it be - 1/5* (1/(1+ (x/5))) or am I just barking up the wrong tree?
If I diff geometric series ... SIGMA X^n to SIGMA nX^(n-1) , what do I do with the 1/5 and x/5 ? Just geeting confused at this point as to what the final pwr series representation should even look like?
tks