Power Rules of Derivatives

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Calc12

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I am completely lost, please advice what steps to take?


The motion of an avalanche is described by s(t) = 3t^2, where s is the distance in metres travlled by the leading edge of the avalanche at t seconds.

a) Find the distance travelled from 0 to 5 s

b) find the rate at which the avalanche is moving from 0 s to 10 s

c) find the rate at which the avalanche is moving at 10 s

d) How long, to the nearest second, does the leading edge of the avalanche take to move 600 m?
 
Calc12 said:
I am completely lost, please advice what steps to take?


The motion of an avalanche is described by s(t) = 3t^2, where s is the distance in metres travlled by the leading edge of the avalanche at t seconds.

a) Find the distance travelled from 0 to 5 s = s(5) - s(0) ..............Do you understand why that should be so?

b) find the rate at which the avalanche is moving from 0 s to 10 s

c) find the rate at which the avalanche is moving at 10 s

d) How long, to the nearest second, does the leading edge of the avalanche take to move 600 m?
Click to expand...
 
Calc12 said:
No, please elaborate!
Click to expand...

I do not think you are ready for this class - specially online.

The first part of the problem is taught in pre-calculus - where "meaning" of functional relationship is taught. You should take a class in that prior to attempting this class.
 
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