Position and Velocity

uberathlete

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Joined
Jan 16, 2006
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48
Hi again everyone. I have a solution to this problem but I'm not really sure if it's correct. The problem is:

The position of a fly at time t is given (x, y, z) = (t, t^2, 1+t^2). A light shines down on the fly from the point (0, 0, 3) and casts a shadow on the xy-plane. What is the position and velocity of the shadow at time t = 1?

What I have is:

The position of the fly at t is (x,y,z) = (t, t^2, 1+t^3). The shadow is on the xy-plane, so it's position is (x,y,z) = (t, t^2, 0). Therefore it's velocity is v(t) = (1, 2t, 0). So at time t = 1, the position of the shadow is: (x, y z) = (1, 1, 0) and its velocity is v(t) = (1, 2, 0).

Now I'm not really sure if this is correct, cuz the light source is at (0, 0, 3) while the fly at time t=1 is at (1, 1, 2), so essentially, the light is casting a diagonal light on the fly which may affect the position of the shadow. I'm not really sure how to go about this, so if anyone could lend me a hand or a thought, it'd be greatly appreciated. Thanks!
 
I have a couple very tentative equations that I offer with no guarantees. The primes are on the xy plane. The non-primes are the fly's coordinates.
dx'=3x*dz/(3-z)^2+3dx/(3-z)
dy'=3y*dz/(3-z)^2+3dy/(3-z)
That's all I have so far. I'm running out of time and can't verify nor disprove them.
The diagonal light rays definitly have an effect.
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Gene
 
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