Polynomimal

[lovelysj]

Can someone plz help me I dont want to fail my class but i am so lost. I dont know if i need to find x or the year

The polynomial 0.0038x^3+0.0042x^2+0.126+1.76 gives the approximate total earnings of a company, in millions of dollars, where the x represents the number of years since 1996. this model is valid for the years from 1996-2000 Determine the earnings for the 1999 round the answer to two decimals if necessary.

the x^3 and x^2 and powers or exponents

thanks for any help

 

[Deleted member 4993]

Can someone plz help me I dont want to fail my class but i am so lost. I dont know if i need to find x or the year

The polynomial 0.0038x^3+0.0042x^2+0.126+1.76 gives the approximate total earnings of a company, in millions of dollars, where the x represents the number of years since 1996. this model is valid for the years from 1996-2000 Determine the earnings for the 1999 round the answer to two decimals if necessary.

the x^3 and x^2 and powers or exponents

thanks for any help

'x' is the number of yeras since 1996

for 1997 - it is 1 year since 1996 - hence x = 1
for 1998 - it is 2 years since 1996 - hence x = 2

Your year of interest is 1999 - so what is the value of 'x' for 1999?..............................(1)

earning = 0.0038x^3 + 0.0042x^2 + 0.126 + 1.76 ...............................................(2)

Now evaluate (2) for the value of 'x' found in (1)

Please show us your work - indicating exactly where you are stuck, so that we know where to begin to help you.

 

[chivox]

The polynomial, I assume (because the typo is obvious), is

\(\displaystyle 0.0038 x^3 + 0.0042 x^2 + 0.126 x + 1.76\)

where x represents the number of years since 1996.

The variable x doesn't represent the actual year, but it represents the number of years since 1996, like you said. It would be \(\displaystyle 1997 - 1996 = 1\), for example, for 1997. What is it in 1999?

It just asks you to do the arithmetic (after plugging in the x) to find total earnings. So, what is x? Substitute and compute.... It's that simple.

 

[lovelysj]

Thank you so much. I am going to try that now. I did not know how to add the exponents up top i will go back and read to see if i can find it

 

[Denis]

I did not know how to add the exponents up top i will go back and read to see if i can find it

Huh? 4^3 = 4 times 4 times 4 ; you didn't know that ? :shock:

 

[chivox]

I did not know how to add the exponents up top i will go back and read to see if i can find it

?? That part you did right: Use the caret (shift-6) to show exponents. The typo I was talking about was leaving the the x out of the first-order term. Or, did you mean to add to constants at the end? ??

Anyway, just read the problem carefully to figure out what the variables stand for, then figure out what you know about those quantities from the problem.