polynomials...a few different problems

[erin524]

These are 3 separate problems.


Simplify: bc+5bx-2cx-10x^2/c^2+5cx-3bc-15bx division symbol 4x^2-b^2/2x^2+15bx+7b^2


Solve for b: 5/a-3/b=4/c


Divide: (10x^3-41x^2+41x-10) division symbol (5x-3)



I really don't even know where to begin. Thanks in advance.

 

[Denis]

AGAIN: check for BRACKETS :shock:

WHY do you not know where to begin? Missed math classes?

 

[Aladdin]

These are 3 separate problems.


Simplify: bc+5bx-2cx-10x^2/c^2+5cx-3bc-15bx division symbol 4x^2-b^2/2x^2+15bx+7b^2


Solve for b: 5/a-3/b=4/c


Divide: (10x^3-41x^2+41x-10) division symbol (5x-3)



I really don't even know where to begin. Thanks in advance.

For the third one,is that what you meant:?:
\(\displaystyle \frac{10x^3-41x^2+41x-10}{5x-3}\)

For the second:solve b ::
\(\displaystyle \frac{5}{a}-\frac{3}{b}=\frac{4}{c}\)

\(\displaystyle \frac{5b}{ab}-\frac{3a}{ab}=\frac{4}{c}\)

\(\displaystyle \frac{5b-3a}{ab}=\frac{4}{c}\)

\(\displaystyle {c(5b-3a)}={4ab}\)

5bc-3ac=4ab

5bc-4ab=3ac

(b)(5c-4a)=3ac

\(\displaystyle b=\frac{3ac}{5c-4a}\)

 

[erin524]

on the third one there is just a division symbol. it is lined up in the order i wrote it, but I could not find a division symbol on my key board. Thank you for your help.

 

[erin524]

I am unable to write the problems exactly as they appear, because of the computer. I do not know how to put them in perfect algebra form on this typewriter.

 

[erin524]

These are 3 separate problems.


Simplify: bc+5bx-2cx-10x^2/c^2+5cx-3bc-15bx division symbol 4x^2-b^2/2x^2+15bx+7b^2


Solve for b: 5/a-3/b=4/c


Divide: (10x^3-41x^2+41x-10) division symbol (5x-3)



I really don't even know where to begin. Thanks in advance.

For the third one,is that what you meant:?:
\(\displaystyle \frac{10x^3-41x^2+41x-10}{5x-3}\)

For the second:solve b ::
\(\displaystyle \frac{5}{a}-\frac{3}{b}=\frac{4}{c}\)

\(\displaystyle \frac{5b}{ab}-\frac{3a}{ab}=\frac{4}{c}\)

\(\displaystyle \frac{5b-3a}{ab}=\frac{4}{c}\)

\(\displaystyle {c(5b-3a)}={4ab}\)

5bc-3ac=4ab

5bc-4ab=3ac

(b)(5c-4a)=3ac

\(\displaystyle b=\frac{3ac}{5c-4a}\)

Thank you for solving this, this was a big help....

As for the third one, it is lined up exactly as I wrote it, I just don't have an actual division symbol on my keyboard. However, the way you wrote it is probably the same thing. Thank you.

 

[erin524]

AGAIN: check for BRACKETS :shock:

WHY do you not know where to begin? Missed math classes?

This is not for a class, these problems are off of a review sheet for a placement test. I took the class 12 years ago, and I thought if I saw these problems solved, it would jog my memory and I will be able to solve similar ones on my own.