Polynomial functions - pls help me show values

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Bahnanna

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For how many values of 'a' do these equations have real solutions
Xsq + ax + 1 = 0 and Xsq - x - a = 0
I get once
(Sorry iPad doesn't have square symbol)
 
Last edited:
Bahnanna said:
For how many values of 'a' do these equations have real solutions
Xsq + ax + 1 = 0 and Xsq - x - a = 0
I get once
(Sorry iPad doesn't have square symbol)
Click to expand...

What does Xsq signify? Is it x2?

If it is - then use the rule of discriminant (\(\displaystyle \sqrt{B^2 - 4*A*C}\) of the quadratic equation (Ax2 + Bx + C = 0)
 
Polynomial s

I'm sorry I forgot part of the question, it was supposed to be how many values of 'a' do these equations:
x^2 + ax + 1 = 0 and
x^2 - x - a = 0
have a common real solutions. I was able to get to the (x + 1)(a + 1) = 0 but was unable to understand how that related to the question of common solutions and was wondering if you could help.
 
Bahnanna said:
I'm sorry I forgot part of the question, it was supposed to be how many values of 'a' do these equations:

x^2 + ax + 1 = 0

and

x^2 - x - a = 0

have a common real solutions. I was able to get to the

(x + 1)(a + 1) = 0 this is the common solution.

What is the "common" value of 'x' from this equation? What is the value of "a" at this value of 'x'?

but was unable to understand how that related to the question of common solutions and was wondering if you could help.
Click to expand...
.
 
Polynomials

Oh I understand now,
So I got a=2 for both equations
Is that correct??
 
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