Consider a box with dimensions 3cm x 5xm x 11cm. If all of its dimensions are increased by x cm, what values of x will give a box with a volume between 300cm3 and 900cm3?
I hope everyone can help me out with this problem. I have been taking the Advanced Function grade 12 math course so that I can go back to college. So far, I have come up with the following inequality:
300<=(x+3)(x+5)(x+11)<=900
I have tried split this in 2 simpler inequalities
a. 300<=(x+3)(x+5)(x+11)
b. (x+3)(x+5)(x+11) <= 900
When I expanded the terms, I got stuck. With (a), I have reached this far
0 <= x^3 + 19x^2 + 103x - 135
My plan is to find the 1st x - intercept and then conduct the synthetic division following by an interval chart/ table. Nevertheless, I still can't find an x-intercept.
Please help me out. Thank you.
I hope everyone can help me out with this problem. I have been taking the Advanced Function grade 12 math course so that I can go back to college. So far, I have come up with the following inequality:
300<=(x+3)(x+5)(x+11)<=900
I have tried split this in 2 simpler inequalities
a. 300<=(x+3)(x+5)(x+11)
b. (x+3)(x+5)(x+11) <= 900
When I expanded the terms, I got stuck. With (a), I have reached this far
0 <= x^3 + 19x^2 + 103x - 135
My plan is to find the 1st x - intercept and then conduct the synthetic division following by an interval chart/ table. Nevertheless, I still can't find an x-intercept.
Please help me out. Thank you.