polynomial equations: x+1= 9x(cubed) + 9x^

bandaidgirl

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Sep 3, 2006
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solve polynomial equation by factoring and using zero-product principle

x+1= 9x(cubed) + 9x^

9x(cubed) +9x^-x-1=0
9x^(x+1)-(x-1)=0
(x+1)(9x^-1)=0


how do i get both of the "1" either + or - so i can finish this
 
bandaidgirl said:
x+1= 9x(cubed) + 9x^
The "9x(cubed)" means, "9x<sup>3</sup>" (that is, "9x^3"), right? But what does the "9x^" mean?

bandaidgirl said:
how do i get both of the "1" either + or - so i can finish this
I'm sorry, but I don't know what this means...?

Eliz.
 
Re: polynomial equations

Hello, bandaidgirl!

From your work, I'm sure that \(\displaystyle x^\) means "x squared".


Solve the polynomial equation by factoring and using zero-product principle
. . . \(\displaystyle x\,+\,1\:=\: 9x^3\,+\, 9x^2\)

\(\displaystyle \;\;9x^3\,+\,9x^2\,-\,x\,-\,1\:=\:0\)

\(\displaystyle \;\;9x^2(x\,+\,1)\,-\,(x\,+\,1)\:=\;0\)

\(\displaystyle \;\;(x\,+\,1)(9x^2\,-\,1)\:=\:0\;\;\) . . . Nice factoring!

Now factor again: \(\displaystyle \,(x\,+\,1)(3x\,-\,1)(3x\,+\,1)\:=\:0\)

Got it?

 
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