http://img80.imageshack.us/img80/1723/helpmeiq4.png
The graph is sorta misdrawn but can anyone tell me if my setup is correcT?
The graph is sorta misdrawn but can anyone tell me if my setup is correcT?
polar area inside circle w/ r = 2, outside cartiod w/ r=...
- Thread starter kpx001
- Start date
D
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Re: polar area
I do not understand your set-up.
The limit on r dr should be 2(1-sinT) to 2
The limit on dT should be 0 to \(\displaystyle \pi\)
kpx001 said:
I do not understand your set-up.
The limit on r dr should be 2(1-sinT) to 2
The limit on dT should be 0 to \(\displaystyle \pi\)
Re: polar area
Looks like you have the circle right, but the cardioid...............
Find the area of the circle and find the area of the cardioid, then subtract them. That will give the required area.
\(\displaystyle \frac{1}{2}\int_{0}^{\pi}4d{\theta}-2\int_{0}^{\pi}(1-sin{\theta})^{2}d{\theta}\)
I will leave the integration up to you. Okey-doke?.
Looks like you have the circle right, but the cardioid...............
Find the area of the circle and find the area of the cardioid, then subtract them. That will give the required area.
\(\displaystyle \frac{1}{2}\int_{0}^{\pi}4d{\theta}-2\int_{0}^{\pi}(1-sin{\theta})^{2}d{\theta}\)
I will leave the integration up to you. Okey-doke?.
