point on y = x + 1 that is sqrt[5] units from point (3, 1)

[rebecca]

A line has an equation y = x + 1.

I need to find the point on the line where the distance between that point and point (3, 1) is the square root of 5.

I know how to use the Distance Formula. But how does that help me on this exercise, or does it at all? How can I use the y = x + 1 line equation?

 

[galactus]

Try:

\(\displaystyle \L\\(x-3)^{2}+(y-1)^{2}=5\)

But, you know y=x+1

\(\displaystyle \L\\(x-3)^{2}+((x+1)-1)^{2}=5\)

Solve for x

 

[rebecca]

Of course! Thanks. I should have known that.