plz help... trig functions...

jhrose3007

New member
Joined
Oct 8, 2008
Messages
2
tan? = (sec?+1)
(sec? -1) ( tan?)






cos? + (1 + sin?) = 2 sec?
(1 + sin?) (cos?)



cot(x) + tan(x) =csc(x)
sec(x)
 
jhrose3007 said:
tan? = (sec?+1)
(sec? -1) ( tan?)






cos? + (1 + sin?) = 2 sec?
(1 + sin?) (cos?)



cot(x) + tan(x) =csc(x)
sec(x)

Please share with us your work/thoughts - indicating exactly where you are stuck - so that we know where to begin to help you.
 
the first one...

(tan[theta])[squared]
(sec[theta] -1)[squared]

tan[squared][theta]
sec[squared][theta] - 2sec[theta] +1

tan[squred]
tan[squared][theta] - 2sec[theta]

sec[squared][theta] + 1
-tan[theta] -2sec[theta]

im confused at this point....
 
jhrose3007 said:
Code:
   tan?            sec?+1
----------  =   -----------
 sec? -1           tan?

\(\displaystyle \frac{\tan(\theta)}{\sec(\theta) \, - \, 1}\)

\(\displaystyle = \, \frac{\tan(\theta)}{\sec(\theta) \, - \, 1}\cdot\frac{1+\sec(\theta)}{1+\sec(\theta)}\)

\(\displaystyle = \, \frac{\tan(\theta)\cdot [1+\sec(\theta)]}{\sec^2(\theta) \, - \, 1}\)

\(\displaystyle = \, \frac{\tan(\theta)\cdot [1+\sec(\theta)]}{\tan^2(\theta)}\)

Now continue....
Code:
   cos?            (1 + sin?)                             
-----------   +   -----------  =  2 sec?
(1 + sin?)          (cos?)
Follow the principle above....
Code:
cot(x) + tan(x)      
-----------------  =  csc(x)
        sec(x)

Convert everything to sin(x) and/or cos(x) and continue.....
 
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