Iceycold12
Junior Member
- Joined
- Feb 24, 2012
- Messages
- 55
Hey.
Evaluate: x^2-5(3x-12) for x=10
Plug in: 10^2-5(3(10)-12) -> 100-5(30-12)
Now I forgot something here (2 1/2 months of no Algebra is definitely showing it's side effects)
Do you know simplify the parenthesis to (18) (30-12) and then multiply by -5 by 18 so it ends up as 100-90 = 10 or do I distribute the -5 the moment I evaluate for the 10 I plugged in (3(10)-12), so 100-5(30-12) distribute the -5 to both, so it simplifies to 100--150+60 -> 100+150+60 = 310. Another attempt I gave it at it which I'm most certain is wrong is simplify (3(10)-12) to (30-12) then remove the parenthesis so it's just one straight add & subtract problem but I highly doubt just removing the parenthesis is the right step to take: 100-5+30-12.
Thanks, if you need me to explain better just let me know.
Evaluate: x^2-5(3x-12) for x=10
Plug in: 10^2-5(3(10)-12) -> 100-5(30-12)
Now I forgot something here (2 1/2 months of no Algebra is definitely showing it's side effects)
Do you know simplify the parenthesis to (18) (30-12) and then multiply by -5 by 18 so it ends up as 100-90 = 10 or do I distribute the -5 the moment I evaluate for the 10 I plugged in (3(10)-12), so 100-5(30-12) distribute the -5 to both, so it simplifies to 100--150+60 -> 100+150+60 = 310. Another attempt I gave it at it which I'm most certain is wrong is simplify (3(10)-12) to (30-12) then remove the parenthesis so it's just one straight add & subtract problem but I highly doubt just removing the parenthesis is the right step to take: 100-5+30-12.
Thanks, if you need me to explain better just let me know.