Please solve my second question

Shoaibraza134

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Aug 28, 2020
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Few hours ago i posted a question and i got answer but now i want answer for my second question please see attachment
 

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Let's make it more readable:
1598639027330.png

Both of these questions are out of place in a mathematics exam (if that is what this is); nor are they really "IQ questions" as you implied in the other thread. They are entirely a matter of guessing. And I have no idea what "research" means here, unless they mean to do a search because the questions were borrowed from some site.

I think you have no obligation to spend any time working on these.
 
You want an answer? Then you have come to the wrong forum as we do not give out answers. If you got an answer for another post then someone did not follow the rules of this forum. This is a math help forum where we help students solve their problems vs solving the problem for them.

To be honest, helpers on this forum do not like such problems as there are no right answers and that is why you were probably given an answer.

One answer can be that to go from 6 to 10 you increased by 4, so to go from 10 to ? you should increase by 4.
Another answer can be that you multiply the 6 by 10, get 60, then subtract 50. Now do the same to 10--multiply 10 by 10 and subtract 50 and ? = 50.
Yet another answer is subtract 4 from 6 and then multiply by 5. Doing the same to 10 will yield 30. So ? =30.

The rules for the numbers in the 1st position does not have to be the same for the numbers in the 2nd position. Same for the 3rd position.

I know I said that we do not give out answers yet I gave three valid answers. I am showing how ridiculous these type of problems are. That is not your fault.
 
What I would do for the first one:
"If 32 and 43 make 35 then 76 and 15 make ____"
is look for a linear relation, just because that is easiest. That is, look for numbers, a and b, such that 32a+ 43b= 35 and a+ b= 1. multiply a+ b= 1 by 32 to get 32a+ 32b= 32 and subtract that from 32a+ 43b= 35. (32- 32)a+ (43- 32)b= 11b= 35- 32= 3. Then b= 3/11. Putting that into a+ b= 1, a+ 3/11= 1 so a- 1- 3/11= 8/11.

Now, 75a+ 15b= 600/11+ 45/11= 645/11. My answer would be that "76 and 15 make 645/11".

Of course, I have no way of knowing if that was what was intended but it meets all the requirements of the problem!

For the next, I would note that 3+ 6+ 11= 20 and 13+ 10+ 7= 30. Aha! I say. I should find "?" so that 15+ ?+ 3= 18+ ?= 40! That is, ?= 40- 18= 22.

Again, I have no way of knowing if that was intended but it meets all the requirements of the problem.
 
[MATH](3 + 2) \cdot (4 + 3) = 5 \cdot 7 = 35[/MATH]
[MATH](7 + 6) \cdot (1 + 5) = 13 \cdot 6 = 78[/MATH]
 
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