please help???

mathhelp1a

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csc ^2 (4-3x)

differentiate?
csc ^ 2 (-3) + cot ^ 2 + 1 (4-3x)

simplify??

csc^2 -1 (4-3x)
 
mathhelp1a said:
csc ^2 (4-3x)

differentiate?
csc ^ 2 (-3) + cot ^ 2 + 1 (4-3x)

simplify??

csc^2 -1 (4-3x)

The derivative pf csc^2 (4 - 3x) is 2 csc (4 - 3x) • [-csc (4 - 3x) cot (4 - 3x)] • (-3)

Chain Rule. Remember?
 
Yes. the derivative of csc(u) is -cot(u).

Either way is cool because tan(-x)=-tan(x)

\(\displaystyle \frac{d}{dx}[csc(4-3x)]=-(-3)cot(4-3x)=3cot(3x-4)\)

But, you have a squared term.

\(\displaystyle \frac{d}{dx}[csc^{2}(3x-4)]=-6cot(4x-4)csc^{2}(3x-4)\)
 
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