Please help

[pudinrcks]

hey i had these on some math hw and i was wondering if i was correct or not.


1) if sinx=-3/5 and cos <0, then x terminates in Quadrant...III??

2) In which quadrant do both the cosecant and secant functions have negative values? ...I thought it would be III because of the reciprocals of cos and sec, but i was not sure.

3) name the quadrant in whcih angle x may lie if secx>0 and cotx<0...IV again because of the reciprocals? I'm not sure if the reciprocals negate or not.

4) ???Express csc 157 as a csc function of a positive acute angle...hmmmm i thought it might be csc 67 because I subtracted 90 from 157

5) ????(I had the same problemt as the one before) Express sec 135 as a sec function of a positive acute angle...sec 45???

6) This one I am not entirely sure on....If y is an angle in standard position, evaluate ALL remaining trig functions of y in simplest readical form if cos=-9 and y is not a second-quadrant angle.

sin=-sqare root of 19/10
tan=square root of 19/9
sec=-10/9
cot=9/square root of 19
csc=-10/square root of 19


THANKS SOO MUCH FOR ANY HELP YOU CAN GIVE ME i'm sorry about writing out square root but i don't know how to make the symbol

 

[Gene]

1) In quadrant III cos(x) is negative. It is positive (>0) in I & IV
2) Correct
3) Correct
4) Close. Csc is symetrical around 90° so csc(x)=csc(90+x)=csc(90-x)
csc(157) = csc(90+67) = csc(90-67)
5) cos(90-x) = -cos(90+x). Same approach.
6) Something wrong here. If you are saying cos(y)=-9. Sine and cosine are both always between -1 and 1.