please help

G

Guest

Guest
Given f(x)=x^3-2x^2+x-5; D={Reals}, find f(-2)
How do you solve this problem?
I found that f(-2)=-2x^2=4x-2+10/x
I would like to know if this is the answer or if I need to solve for x or f to find the answer and if so how.
 
I'm not really clear on what you did to find the answer.

What you were given is a function called f. This function takes one input, called x. When you see f(-2), it means find the value of f when x=-2. In other words, substitute -2 for all the x's in the function.

In this case:
f(x)=x^3-2x^2+x-5
f(-2)=(-2)^3 - 2*(-2)^2 - 2 - 5
f(-2)=-8 - 8 - 2 - 5
f(-2) = -23

Hope this helps!
Ted
 
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