Please help with these asap I need them by March 9th!!!!

[Haharps]

Factoring ahhh!
3x-{5x-[7x-(4x-(3x-(3x+1))]}=3x+5

Matrix
w+x+y+z=2
w+2x+2y+4z=1
w-x+y+z=6
w-3x-y+z=2

Multiply
(x-1)(x^2+x+1)(x^3=1)

 

[WTF?]

w+x+y+z=2
w+2x+2y+4z=1
w-x+y+z=6
w-3x-y+z=2

Set up the matrix.

[1 1 1 1
1 2 2 4
1-1 1 1
1-3-1 1]

and find the inverse.

then, multiply by
[2
1
6
2]

 

[Gene]

More like un-factoring!
3x-{5x-[7x-(4x-(3x-(3x+1))]}=3x+5
3x-{5x-[7x-(4x-(3x-3x-1))]}=3x+5
3x-{5x-[7x-(4x+1)]}=3x+5
3x-{5x-[3x-1]}=3x+5
3x-{2x+1}=3x+5
x-1=3x+5

Matrix
w+x+y+z=2
w+2x+2y+4z=1
w-x+y+z=6
w-3x-y+z=2

+1 +1 +1 +1 +2
+1 +2 +2 +4 +1
+1 -1 +1 +1 +6
+1 -3 -1 +1 +2
Yup, it is a matrix.

Multiply
(x-1)(x^2+x+1)(x^3=1)
The answer is zero if you mean what you typed.
(x^3=1) is a logical term. It = 0 if x <> 1 and it = 1 if x = 1.