Please help with problem quickly, thanks. :)

[dawnjoennikki98]

What I need to do is find digits A and B in the number below so that the following conditions are true.

* The 5-digit number must be divisible by 4
* The 5-digit number must be divisible by 9
* Digit A cannot be the same as digit B
36,A2B

 

[Loren]

What I need to do is find digits A and B in the number below so that the following conditions are true.

* The 5-digit number must be divisible by 4
* The 5-digit number must be divisible by 9
* Digit A cannot be the same as digit B
36,A2B

Rules of divisibility by 4 and 9...

If the sum of the digits is divisible by 9, the number is also.
If the last two digits form a number divisible by 4, the number is also.

Therefore, 3+6+A+2+B must be divisible by 9.
2B must be a number divisible by 4. Since the first digit is a 2, 2B must be 20, 24, or 28.

Certainly, you can take it from there.

P.S. I get two possible answers.

 

[dawnjoennikki98]

Thank you so much! That was a great explanation.
Dawn