tigerpawz74
New member
- Joined
- Dec 16, 2005
- Messages
- 14
If one of the equal legs of an isoceles triangle is three times as long as the other side and the perimeter equals 21, how long is the other leg?
I set this up using X as the unknown leg, then 3X for each of the equal legs, so that 3x + 3x + x = 21; so, 7x = 21. Dividing out, x = 3........then if you plug in 3 for x, each of the equal legs = 9 and the other leg is 3. Adding 9 + 9 + 3, you get 21 for the perimeter. Is this correct? Thanks
I set this up using X as the unknown leg, then 3X for each of the equal legs, so that 3x + 3x + x = 21; so, 7x = 21. Dividing out, x = 3........then if you plug in 3 for x, each of the equal legs = 9 and the other leg is 3. Adding 9 + 9 + 3, you get 21 for the perimeter. Is this correct? Thanks