sarahjoy00
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Add the proper constant to the binomial so that the resulting trinomial is a perfect square trinomial. Then factor the trinomial.
x2 - 3x
I am so confused!
x2 - 3x
I am so confused!
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Please HELP w/binomial squares
- Thread starter sarahjoy00
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sarahjoy00 said:Add the proper constant to the binomial so that the resulting trinomial is a perfect square trinomial. Then factor the trinomial.
x2 - 3x
I am so confused!
perfect square trinomial would look like:
(x + a)[sup:3rbhd3vl]2[/sup:3rbhd3vl] = x[sup:3rbhd3vl]2[/sup:3rbhd3vl] + 2ax + a[sup:3rbhd3vl]2[/sup:3rbhd3vl]
so you are missing a[sup:3rbhd3vl]2[/sup:3rbhd3vl] part - that would be your proper constant.
How would you find 'x'?
Look at the trinomial equation carefully - term by term....
Subhotosh Khan said:sarahjoy00 said:Add the proper constant to the binomial so that the resulting trinomial is a perfect square trinomial. Then factor the trinomial.
x2 - 3x
I am so confused!
perfect square trinomial would look like:
(x + a)[sup:3992n95c]2[/sup:3992n95c] = x[sup:3992n95c]2[/sup:3992n95c] + 2ax + a[sup:3992n95c]2[/sup:3992n95c]
so you are missing a[sup:3992n95c]2[/sup:3992n95c] part - that would be your proper constant. -- > 2a = -3 :wink: Is it right , Sarah !
How would you find 'x'?
Look at the trinomial equation carefully - term by term....