please help, thank you very much

d1truth

New member
Joined
Feb 3, 2005
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10
for a two year select and ultimate mortality you know:

a. q[x] = (1-2k) qx
b. q[x]+1 = (1-k) q(x+1)
c. I[32] = 90
d. I32 = 100
e. I33 = 90
f. I34 = 63

calculate I[32] + 1
 
You're going to have to tell me what the "I" function is.

Do you mean "L"?
 
And what do the brackets mean?

Thank you.

Eliz.
 
The brackets are no problem. They indicate that the data are in the "select" period.

qx means the mortality rate for a person age x outside the select period
q[x] means the mortality rate for a person age x inside the select period
 
OK, I'll assume those are "L"s and you mean to be reporting a Survivorship function.

L<sub>33</sub>/L<sub>32</sub> = 90/100 = 9/10
----- Giving q<sub>32</sub> = 1-(9/10) = 1/10
L<sub>34</sub>/L<sub>33</sub> = 63/90 = 7/10
----- Giving q<sub>34</sub> = 1-(7/10) = 3/10

This makes

q<sub>[32]</sub> = (1-2*k)*(1/10)
q<sub>[32]+1</sub> = (1-k)*(3/10)

p = 1-q

Finally, L<sub>[32]</sub>*(p<sub>[32]</sub>)*(p<sub>[32]+1</sub>) = 63

90*(1-q<sub>[32]</sub>)*(1-q<sub>[32]+1</sub>) = 63
90*(1-((1-2*k)*(1/10)))*(1-((1-k)*(3/10))) = 63

I get k = -7, which makes no sense and k = 1/6.

L<sub>[32]+1</sub> = 90*(1-((1-2*k)*(1/10))) = 84
-----
Checking: L<sub>[32]+2</sub> = L<sub>34</sub> = 84*(1-((1-k)*(3/10))) = 63
-----
 
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