Can you think of a function statement where exchanging 'x' with 'y' (and vice versa) will not change the graph?Find an example of a function that produces the same image when its graph is reflected in the y-axis as it does when its graph is reflected in the x-axis. Graph the equation and the two images
You might imagine doing the two transformations, one after the other: reflect a graph in the y-axis, and then reflect the result in the x-axis. Do you see that if this returns the graph to the original, it will also satisfy the problem?Find an example of a function that produces the same image when its graph is reflected in the y-axis as it does when its graph is reflected in the x-axis. Graph the equation and the two images
Why would you say that? There are many functions that work. I think you may be misreading something.I don't think that anything would be a function except other than the function that contains just (0,0)
But you should draw a function, since that's what they ask for, and it doesn't have to be only in the first quadrant. (I recommend just keeping x>0.) And this exercise will then result in a function that works, though one might not immediately see the key idea I hinted at, about symmetry.If it does not [have] to be a function, then draw anything in quadrant 1 (and I really mean anything). Then reflect that across the y-axis. Then reflect the whole graph across the x-axis.
Now look at this graph and think what might work.
xy = Constant ....... it is a rectangular hyperbola.I don't think that anything would be a function except other than the function that contains just (0,0)
Find an example of a function that produces the same image when its graph is reflected in the y-axis as it does when its graph is reflected in the x-axis. Graph the equation and the two images
Can you think of a function statement where exchanging 'x' with 'y' (and vice versa) will not change the graph?
I think you may be misreading the problem, though this is a valid answer. It is not about exchanging x and y (reflecting in y=x), but about reflecting in both x and y axes.xy = Constant ....... it is a rectangular hyperbola.
Thanksxy = Constant ....... it is a rectangular hyperbola.
Yes ... I surely did. Once my mind got trapped in f(x*y) as solution, there was no escape.I think you may be misreading the problem, though this is a valid answer. It is not about exchanging x and y (reflecting in y=x), but about reflecting in both x and y axes.The answer is: Any odd function.