Please help me with evaluating this function

[dbonham1]

Given J (t) = 3tsq-t J=0
I am having trouble getting started since there are two expressions. This is what I came up with. J(o) = 3(t-2)2sq - (t-0) = J=3(o-2) - (t-0) =3. Thank you

 

[wjm11]

Given J (t) = 3tsq-t J=0

The notation is unclear to me. I will assume that J(t) represents a function. Had the second equation been J(t) = 0 (instead of just J= 0), that would have indicated that the function J(t) is always equal to 0 no matter what the value of t is. If that is what is meant by J = 0, then

J(t) = 3tsq-t =0
t(3sq – 1) = 0

so t = 0 or (3sq – 1) = 0

(3sq – 1) = 0
3sq = 1
sq = 1/3

Please verify the problem is correctly typed or if there is information/instructions with the problem that you have not stated.

 

[mmm4444bot]

Given J (t) = 3tsq - t J = 0 …

… J(o) = 3(t - 2) 2sq - (t - 0) = J = 3(o - 2) - (t - 0) = 3

Hi dbonham:

Yikes! What a mess.

Here are some basic guidelines for typing math:

List equations vertically, not horizontally. In other words, type one equation per line, double-spaced.

Do not put a space between the name of a function and the parentheses. In other words, type J(t) instead of J (t). [A space might denote implied multiplication.]

Do not type the letter o for the number 0. Letters represent unknown numbers, just like s and q.

Type a space on both sides of plus signs, subtraction signs, equal signs.

You'll also benefit from checking out KARL'S NOTES FOR TYPING MATH.

Finally, when submitting requests for help at this site, ALWAYS include the instructions that come with the exercise. I can't tell what you've been asked to do with what!

We look forward to seeing your repost of the entire exercise.

Cheers,

~ Mark

 

[dbonham1]

The question askes
Given J(t)=3tsq-t, find
b. J(0)

I retyped the problem using the instructions. Has this change the way I need to figure this problem? Thanks.

 

[Loren]

The question askes
Given J(t)=3tsq-t, find
b. J(0)

Maybe tsq means t[sup:x8s91qah]2[/sup:x8s91qah]???

If so your problem becomes J(t) = 3t[sup:x8s91qah]2[/sup:x8s91qah]-t.

If t = 0, you are supposed to plug zero into the equation in place of t and evaluate the right side. I think you get J(0) = 0.
What does the b mean in your given problem?

 

[mmm4444bot]

By Jove, Loren! I think you've got it.

b. might mean part (b) in some exercise.

Not sure about the thought-process leading to J(0) = 3(t - 2) 2^2 - (t - 0).

 

[dbonham1]

Thank you Lauren You were correcct. I will try and get better at using the right keys to type my questions. Thanks again to all of you.