This appears to be an exercise in writing complex numbers in polar form:
For the first problem let's do that to the [math]\sqrt{6} - 3i \sqrt{2}[/math]. I'll give you the answer, you tell me if you need help with it:
[math]\sqrt{6} - 3i \sqrt{2} = 2 \sqrt{6} e^{-i \pi /3}[/math]
This makes the equation to solve [math]2z^6 + 2 \sqrt{6} e^{-i \pi / 3} z^3 = 0[/math]
So we know that either [math]z^3 = 0[/math] or [math]z^3 + \sqrt{6} e^{-i \pi / 3} = 0[/math]
Can you finish this?
Hint for the second problem. Convert the imaginary numbers into polar form. It simplifies the problem immediately. Give it a try and let us know how you do with it.
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