I don't understand, can you find the answer? the equation of the asymptote y=3^(x+3)+4
E Elle88 New member Joined Mar 17, 2006 Messages 1 Mar 17, 2006 #1 I don't understand, can you find the answer? the equation of the asymptote y=3^(x+3)+4
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Mar 17, 2006 #2 Hello, Elle88! I don't understand, can you find the answer? The equation of the asymptote y = 3x+3 + 4\displaystyle y\:=\:3^{x+3}\,+\,4y=3x+3+4 Click to expand... In general, the exponential function, y = bx\displaystyle y\:=\:b^xy=bx has a horizontal asymptote. \displaystyle \;\;It is y = 0\displaystyle y\,=\,0y=0 (the x-axis) . . . as x → \displaystyle x\,\to\,x→-∞\displaystyle \infty∞. The graph of y = 3x+3 + 4 \displaystyle \,y\:=\:3^{x+3}\,+\,4\,y=3x+3+4 is translated 3 units to the left and 4 units up. Therefore, its horizontal asymptote is: y = 4\displaystyle \,y\;=\;4y=4
Hello, Elle88! I don't understand, can you find the answer? The equation of the asymptote y = 3x+3 + 4\displaystyle y\:=\:3^{x+3}\,+\,4y=3x+3+4 Click to expand... In general, the exponential function, y = bx\displaystyle y\:=\:b^xy=bx has a horizontal asymptote. \displaystyle \;\;It is y = 0\displaystyle y\,=\,0y=0 (the x-axis) . . . as x → \displaystyle x\,\to\,x→-∞\displaystyle \infty∞. The graph of y = 3x+3 + 4 \displaystyle \,y\:=\:3^{x+3}\,+\,4\,y=3x+3+4 is translated 3 units to the left and 4 units up. Therefore, its horizontal asymptote is: y = 4\displaystyle \,y\;=\;4y=4
