Please help I'm so confused

[shorty21432]

Says graph the linear equations and make sure graph meets all requirements. Now I know how to graph, its just coming up with my points. I can't solve the equations, first one is 3x+4y=-12 Somebody anybody Please Please help me

 

[shorty21432]

Still sooooo confused need someone's help bad! my paper is due tomorrow :l

This one is same as last, I don't know how in the world to solve it. I recently had a death in my family and have missed a bunch of school so I'm clueless. this one is -3x+2y-4=0 someone please help i would so very much appreciate any help I could get

 

[pappus]

Says graph the linear equations <--- There is only one equation
and make sure graph meets all requirements. <--- which requirements?
Now I know how to graph, its just coming up with my points. I can't solve the equations, first one is 3x+4y=-12 Somebody anybody Please Please help me

Are you sure that you posted the complete unabridged text of the question?

You didn't tell us for which variable this equation should be solved.

 

[shorty21432]

Are you sure that you posted the complete unabridged text of the question?

You didn't tell us for which variable this equation should be solved.

i believe the requirement is just that u check ur work by making up anther equation that will fit in to match it. its not real important. its for both x and y. its to come up with the ordered pair (x,y,) to plug it into the graph

 

[pappus]

i believe the requirement is just that u check ur work by making up anther equation that will fit in to match it. its not real important. its for both x and y. its to come up with the ordered pair (x,y,) to plug it into the graph

In this case it would be the best to solve for y (I take the 1st equation):

\(\displaystyle 3x+4y=-12\)

\(\displaystyle 4y=-3x-12\)

\(\displaystyle y=-\frac34 x - 3\)

Now use a table: Choose the x-value, plug it into the equation to get the corresponding y-value.

 

[shorty21432]

In this case it would be the best to solve for y (I take the 1st equation):

\(\displaystyle 3x+4y=-12\)

\(\displaystyle 4y=-3x-12\)

\(\displaystyle y=-\frac34 x - 3\)

Now use a table: Choose the x-value, plug it into the equation to get the corresponding y-value.

So would it be -3 I am soooo not good at math at all Its always been a real struggle to me sorry

 

[pappus]

So would it be -3 I am soooo not good at math at all Its always been a real struggle to me sorry

Yes, but only if x = 0.

The value of y depends on the value of x. If x changes then consequently the y-value changes too. (Compare the attached table in my previous post!) That means that you don't get one single value for x and y but that you get an unlimited number of pairs.

 

[shorty21432]

Yes, but only if x = 0.

The value of y depends on the value of x. If x changes then consequently the y-value changes too. (Compare the attached table in my previous post!) That means that you don't get one single value for x and y but that you get an unlimited number of pairs.

I see. so i wonder what exactly was he asking with this question, and which pairs I should plot. Is the other problem the same as this one. -3x+2y>or equal to 6

 

[pappus]

I see. so i wonder what exactly was he asking with this question, and which pairs I should plot. Is the other problem the same as this one. -3x+2y>or equal to 6

1. Plot them all if you like. I've attached a diagram. I've drawn some of the points from the table I posted earlier. You see that all points are placed on a straight line. So all possible points, determined by the equation, form the straight line.

2. This inequality has a half plane as it's graph. The line with the equation
\(\displaystyle -3x+2y\ge6~\implies~\boxed{y\ge\frac32 x + 3}\)
is the lower border of the half plane. (All points are located above the straight line. Therefore the line is the lower border).