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failingalgebra

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Solve by factoring:
x2 – 9x = -20
My work:
x2-9x=20
+9x +9x
x2=20+9x??



Solve using the square root property:
5x^2 = 100



Solve using the square root property:
(x + 8)^2 = 81
2x+16=81
-16 -16
2x=65?

Solve by completing the square:
x^2 + 8x + 13 = 0

Perform the indicated operations:
√[50] + 2√[32] – √[8]

Multiply:
(5√[2] + 3)(√[2] - 2√[3])

Rationalize the denominator:

√[6] - 2/ √[5]
 
Please reply showing the progress you have made on each exercise, so the tutors will know where you are having difficulty.

Thank you.

Eliz.
 
Note: I have numbered the exercises for clarity.

failingalgebra said:
1) Solve by factoring:
x2 – 9x = -20
My work:
x2-9x=20
+9x +9x
x2=20+9x??
To "solve", you need to start by getting everything over on one side, with "zero" on the other. Then you need to factor. Once you have the quadratic factored, you set the factors equal to zero, and solve them.

Do you know how to factor?



failingalgebra said:
2) Solve using the square root property:
5x2 = 100
Assuming "5x2" to mean "5x^2" or "5x<sup>2</sup>", a good first step would be to divide through by 5. Then, in accordance with the instructions, take the square root of each side.

You mention that you have never learned how to solve by square roots. The general process is fairly straight-forward: you have an equation of the form "(variable part)<sup>2</sup> = (number part)", and you take square roots. For instance:

. . . . .\(\displaystyle \large{x^2\,=\,9}\)

. . . . .\(\displaystyle \large{\sqrt{x^2}\,=\,\pm\sqrt{9}}\)

. . . . .\(\displaystyle \large{x\,=\,\pm3}\)



. . . . .\(\displaystyle \large{(x\,-\,3)^2\,=\,10}\)

. . . . .\(\displaystyle \large{\sqrt{(x\,-\,3)^2}\,=\,\pm\sqrt{10}}\)

. . . . .\(\displaystyle \large{x\,-\,3\,=\,\pm\sqrt{10}}\)

. . . . .\(\displaystyle \large{x\,=\,3\,\pm\,\sqrt{10}}\)

...and so forth. Apply this process to your exercise.



failingalgebra said:
3) Solve using the square root property:
(x + 8)2 = 81
2x+16=81
-16 -16
2x=65?
Is the "2" after the parentheses not a square? Is it not an exponent? (You have multiplied through by 2, rather than squaring, is why I ask.)



failingalgebra said:
4) Solve by completing the square:
x2 + 8x + 13 = 0
Are you not familiar with the process of solving by completing the square?



failingalgebra said:
5) Perform the indicated operations:
√[50] + 2√[32] – √[8]
Note that 50 = 2×5×5, 32 = 2×2×2×2×2, and 8 = 2×2×2. Use this to simplify the square roots. Then combine the "like" terms.



failingalgebra said:
6) Multiply:
(5√[2] + 3)(√[2] - 2√[3])
Just use the "FOIL" technique you learned in class.



failingalgebra said:
7) Rationalize the denominator:
2____
√[6] - √[5]
I'm sorry, but I cannot follow this. Please reply with clarification, using the formatting explained in the links in the "Forum Help" pull-down menu at the very top of the page. (Karl's Notes will probably be the easiest formatting to use.)

Thank you.

Eliz.
 
First, if the problem says x² type it as x^2 so the first problem is
x^2-9x=-20
x^2-9x+20=0
To solve by factoring you are aiming for
(x-a)(x-b) = x^2-9x+20
x^2-(a+b)x+ab=x^2-9x+20
So you must find two numbers that when multiplied give 20 and when added give 9. They must both have the same sign so their product is positive. They are factors of 20 which are 1,2,4,5,10 and 20. At least one must be negative so both must be. Can you find two of those factors that add up to 9? replace a and b with them in (x-a)(x-b). That is your answer.
 
Gene said:
First, if the problem says x² type it as x^2 so the first problem is
x^2-9x=-20
x^2-9x+20=0
To solve by factoring you are aiming for
(x-a)(x-b) = x^2-9x+20
x^2-(a+b)x+ab=x^2-9x+20
So you must find two numbers that when multiplied give 20 and when added give 9. They must both have the same sign so their product is positive. They are factors of 20 which are 1,2,4,5,10 and 20. At least one must be negative so both must be. Can you find two of those factors that add up to 9? replace a and b with them in (x-a)(x-b). That is your answer.

so x=5, y=4?
 
failingalgebra said:
so x=5, y=4?
Correct.

"Solve using the square root property:
(x + 8)^2 = 81
2x+16=81
-16 -16
2x=65?"

NO.
x + 8 = sqrt(81) : understand?

You seem to be missing most of the basics...bad teacher? :shock:
 
I'm not sure why Denis gave you a yes. You were looking for a and b, not x and y. I said
replace a and b with them in (x-a)(x-b). That is your answer.
The answer, because you are factoring, is
(x-4)(x-5)=0

Checking: So x = 4 or x = 5
x^2-9x = -20
4^2-9*4 = -20
5^2-9*5 = -20
They work.
 
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