please delete

The log of a product rule:

\(\displaystyle \mbox{ \ln{(2e^x)} = \ln{(2)} + \ln{(e^x)}\)

And \(\displaystyle \mbox{\ln{(e^x)} = x}\) because the natural log (log base e) of x is the inverse function of the exponential, base e, of x .
 
\(\displaystyle \L
\int {\ln (2)dx = \ln (2)x + C}\)
 
lisasayzhi said:
...what happens to the [integral]ln(2)?
The natural log of two is just a number. A messy number, granted, like \(\displaystyle \pi\) or \(\displaystyle e\) or \(\displaystyle \sqrt{2}\), but just a number, nonetheless.

You know how to handle this:

. . . . .\(\displaystyle \int{\,3\,}dx\)

Do the same thing with the integral of ln(2). :wink:

Eliz.
 
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