how do you solve: -2^2+2^2=?
D Deleted member 4993 Guest Mar 15, 2016 #2 Lerato said: how do you solve: -2^2+2^2=? Click to expand... Is it: -(2^2) + 2^2 =? Or: (-2)^2+2^2=?
pka Elite Member Joined Jan 29, 2005 Messages 11,982 Mar 15, 2016 #3 Lerato said: how do you solve: -2^2+2^2=? Click to expand... I would ask you to think about these. For all real x\displaystyle xx we know that −x2≤0 & (−x)2≥0 .\displaystyle -x^2\le 0~\&~(-x)^2\ge 0~.−x2≤0 & (−x)2≥0 .
Lerato said: how do you solve: -2^2+2^2=? Click to expand... I would ask you to think about these. For all real x\displaystyle xx we know that −x2≤0 & (−x)2≥0 .\displaystyle -x^2\le 0~\&~(-x)^2\ge 0~.−x2≤0 & (−x)2≥0 .
