Piston Diameter?

[JTvede]

This May be easy, I am not sure.
If a single piston displaces 202.22 cubic inches,
What is its Diameter?
The reverse of pi R squared = 202.22
then x2
No Math Expert here, I already know that.
Thanks for the help.

 

[Deleted member 4993]

This May be easy, I am not sure.
If a single piston displaces 202.22 cubic inches,
What is its Diameter?
The reverse of pi R squared = 202.22
then x2
No Math Expert here, I already know that.
Thanks for the help.

Incomplete problem - as posted cannot be solved.

 

[HallsofIvy]

Incomplete because the volume a piston displaces depends not only on its radius but also on it "travel length", the distance it moves up in the shaft.

 

[MarkFL]

The diameter is also sometimes referred to as the "bore" and the travel distance as the "stroke."

 

[Probability]

This May be easy, I am not sure.
If a single piston displaces 202.22 cubic inches,
What is its Diameter?
The reverse of pi R squared = 202.22
then x2
No Math Expert here, I already know that.
Thanks for the help.

To calculate the diameter of a cylinder you require to know the force acting in the cylinder on the piston, this can be calculated from the torque and the radius (crank throw) of the crankshaft.

Making a example;

Suppose that the force acting on the piston is Fp, then T = torque and r = radius, therefore T/r = 26^3/6.5883 = 3946.4N

Now lets say that this is a manufacturer recommended specification, thus the force acting on the piston would be equal to the area of the piston, thus equal to Pi r^2 = 3946.4

So, Fp = Pi d^2 / 4

Fp = d = square root 5024 = 70.88mm

 

[Deleted member 4993]

To calculate the diameter of a cylinder you require to know the force acting in the cylinder on the piston, this can be calculated from the torque and the radius (crank throw) of the crankshaft.

Making a example;

Suppose that the force acting on the piston is Fp, then T = torque and r = radius, therefore T/r = 26^3/6.5883 = 3946.4N

Now lets say that this is a manufacturer recommended specification,

thus the force acting on the piston would be equal to the area of the piston, thus equal to Pi r^2 = 3946.4

So, Fp = Pi d^2 / 4

Fp = d = square root 5024 = 70.88mm

Certainly NOT!!!

 

[Probability]

Certainly NOT!!!

Please explain why.

 

[Deleted member 4993]

Please explain why.

thus the force acting on the piston would be equal to the area of the piston, thus equal to Pi r^2 = 3946.4

It is equivalent to claiming that

the number of rooms in any house is same as the street address of the house (one has almost nothing to do with the other).

 

[Probability]

thus the force acting on the piston would be equal to the area of the piston, thus equal to Pi r^2 = 3946.4

It is equivalent to claiming that

the number of rooms in any house is same as the street address of the house (one has almost nothing to do with the other).

Thank you for replying, however I wanted you to explain why but your example is nothing to do with finding the diameter of a cylinder, nor anything to do with my statement in red above, which I will beyond doubt accept could be incorrect if it is proven to be so, but at present is just a disagreement.

I said that the force on the piston Fp = T/r = 26k/6.5883 = 3946.4N

Diameter of the cylinder is;

Force Fp = Pi d^2/4

Force Fp = (3946.4 x 4) / 4 = d^2

d = square root 5024

d = 70.88

Now the radius = 35.44, thus

Area = pi x 35.44^2

area = 3946

The force acting in a closed cylinder must occupy the same space (area) and if this is so then it must be equal to that. Notice also that I advised about manufacturer recommendations here because we must have a standard to apply the maths to otherwise variations in pressure would conclude different areas and diameters?

Although not exactly the same but similar a steel wire with a load applied of 60N creates a stress in the wire, if the wire stress was 3.0MPa the maths would determine the thickness of the wire, and the area of that wire can be used to work out the diameter of the wire the same.