Physics

[valnadam]

I am in beginning algebra and was told this is a phisics probelm :?
In an electrical circuit, the current passing through a conductor varies inversely with the resistance. Suppose that when the current is 8A (amperes), the resistance is 15 ohms. What is the current when the resistance is 4 ohms?

 

[valnadam]

This is the answer I came up with by researching the formula

E=IR
E=15*8
E=120V
--------------
I=E/R
I=120/4
I=30 amperes

 

[Deleted member 4993]

I am in beginning algebra and was told this is a phisics probelm :?
In an electrical circuit, the current passing through a conductor varies inversely with the resistance. Suppose that when the current is 8A (amperes), the resistance is 15 ohms. What is the current when the resistance is 4 ohms?

The correct way to do this problem would be:

I = K/R

IR = K

then

I[sub:2c6rw0k3]1[/sub:2c6rw0k3]R[sub:2c6rw0k3]1[/sub:2c6rw0k3] = I[sub:2c6rw0k3]2[/sub:2c6rw0k3]R[sub:2c6rw0k3]2[/sub:2c6rw0k3]

8*15 = I[sub:2c6rw0k3]2[/sub:2c6rw0k3] * 4

I[sub:2c6rw0k3]2[/sub:2c6rw0k3] = 120/4 = 30 amps