Physics question: Find pendulum's period on Mars

[Timothy]

A pendulum has a peroid of 0.80 s on Earth. What is its period on Mars, where the acceleration of gravity is about 0.37 that on Earth.

I used Formula T=2pi(sq root of L/g).

80=6.28 (sq root of L/9.8)

(80/6.28) ^2 = L/9.8

162= L/9.8

L=1590

On Mars .37 x 9.8 = 3.62 m/s^2

T=6.28(sq root of 1590/3.62)

T=6.28(21)

T= 131s The book says the answer is 1.3s. I think the book is

right, but I can't figure out where I am messing up at.

Thanks Tim

 

[stapel]

What do "T", "L", and "g" stand for?

Thank you!

Eliz.

 

[skeeter]

T = 2pi*sqrt(L/g)

using g = 9.8 m/s² on Earth ...

0.8 = 2pi*sqrt(L/g)

on Mars ...

T = 2pi*sqrt[L/(.37*g)]

setting up a ratio between the two equations yields the equation ...

0.8/T = sqrt(.37)

T = 0.8/sqrt(.37) = 1.3 sec

 

[Timothy]

Thanks for your help Skeeter