Physics question magnitude of acceleration of alpha particles due to force
Hello,
The following question has two parts, I answered the first one (the answer is correct, but I don't know if my method is) and I do not know how to solve the second part (part b)
part a) the nucleus of ^8 Be, which consists of 4 protons and 4 neutrons, is very unstable and spontaneoulsy breaks unto two alpha particles (helium nuclei, each consisting of two protons and two neutrons).
what is the force between the two alpha particles when they are 5.00x10^-15 m apart?
I did:
F= k (q1 xq2)/r^2
charge of proton = (1.6x10^-17 C) so (1.6x10^-17 C)^2=2.56x10^-38C^2
8.99x10^9 N m^2/C^2 (2.56x10^-38C^2 / (5.00x10^-15m)^2)
=9.20576N then 9.20576N times 4 (because they are in total 4 protons +4 neutrons) = 36.8 N = correct answer
part b) what will be the magnitude of the acceleration of the alpha particles due to this force? Note that the mass of the alpha particles is 4.0026u
The answer is 5.54x10^27 m/s^2 but how do i solve it? I am confused in what formula to use.
thank you for your help!
Hello,
The following question has two parts, I answered the first one (the answer is correct, but I don't know if my method is) and I do not know how to solve the second part (part b)
part a) the nucleus of ^8 Be, which consists of 4 protons and 4 neutrons, is very unstable and spontaneoulsy breaks unto two alpha particles (helium nuclei, each consisting of two protons and two neutrons).
what is the force between the two alpha particles when they are 5.00x10^-15 m apart?
I did:
F= k (q1 xq2)/r^2
charge of proton = (1.6x10^-17 C) so (1.6x10^-17 C)^2=2.56x10^-38C^2
8.99x10^9 N m^2/C^2 (2.56x10^-38C^2 / (5.00x10^-15m)^2)
=9.20576N then 9.20576N times 4 (because they are in total 4 protons +4 neutrons) = 36.8 N = correct answer
part b) what will be the magnitude of the acceleration of the alpha particles due to this force? Note that the mass of the alpha particles is 4.0026u
The answer is 5.54x10^27 m/s^2 but how do i solve it? I am confused in what formula to use.
thank you for your help!