The drawing shows a person looking at a building on top of which an antenna is mounted. The horizontal distance between the person's eyes and the building is 85.0 m. In part a the person is looking at the base of the antenna, and his line of sight makes an angle of 35.0° with the horizontal. In part b the person is looking at the top of the antenna, and his line of sight makes an angle of 38.0° with the horizontal. How tall is the antenna?
person looking at antenna mounted on top of building
- Thread starter jferrel8
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Re: ??
Did you make a diagram?. This is an exercise in the law of tangents.
Let x=heigth of antennae and y=height of building.
We can see the height of the antennae is the difference in the tangents.
\(\displaystyle 85tan(38)-85tan(35)\)
Do you follow how I got that?. That is the main thing. Let me know if you don't
Did you make a diagram?. This is an exercise in the law of tangents.
Let x=heigth of antennae and y=height of building.
We can see the height of the antennae is the difference in the tangents.
\(\displaystyle 85tan(38)-85tan(35)\)
Do you follow how I got that?. That is the main thing. Let me know if you don't
